IGCSE chemistry
section 1i
the migration of ions
Introduction
In an electrolysis experiment, the ions migrate towards
electrodes of opposite charge. In the first part of this experiment the
migration of manganate ions is observed. In the second part of this experiment,
silver and chromate ions meet as they migrate towards opposite electrodes.
Silver chromate, an insoluble red compound is formed.
What to record
Draw a diagram to show the filter paper at the end of both
experiments. Mark the ends of the paper with a + or – to show which terminal of
the power supply each end is connected to.
What to do
Part 1
1. Cut a
piece of filter paper slightly smaller than a microscope slide. Draw a faint
pencil line across the middle.
2. Moisten
the filter paper with tap water. Fasten the paper to the slide with crocodile
clips.
3. Use
forceps to put a small crystal of potassium manganate(VII) in the centre of the
paper.
4. Connect
the clips to a power supply set at not more than 20 V DC. Switch on and wait
about ten minutes.
Part 2
1. Cut a
piece of filter paper slightly smaller than a microscope slide. Draw a faint
pencil line across the middle.
2. Moisten
the paper with tap water. Fasten the paper to the slide with crocodile clips.
3. At the end
of the paper where the positive electrode will be placed, moisten the paper
with silver nitrate solution. (Will
stain fingers)
4. At the
end of the paper where the negative electrode will be placed, moisten the paper
with potassium chromate solution. (Toxic).
5. Connect
the clips to a power supply set at no more than 20 V DC. Switch on and wait
about 10 min, or until you see a change.
Safety
Wear eye protection.
Questions
1. Potassium
manganate (VII) consists of two ions – potassium ions and manganate (VII)
ions. One of these ions is coloured. Which is it likely to be?
2. From the
direction of movement, what does this indicate about the charge on the
manganate ion?
3. What is
happening in the second experiment?
4. The
formula of silver nitrate is AgNO3 and potassium chromate is K2CrO4.
Write the ionic formula equation for the reaction.
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